The stopping potential as function of frequency of incident radiation is plotted for two different photoelectric surfaces A and B. The graphs show that the work function of A is
greater than that of B
lesser than that of B
equal than that of B
no comparison
A
lesser than that of B
B
equal than that of B
C
no comparison
D
greater than that of B
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Solution
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From Einstein’s equation ,
eV0=hν–hν0
V0=hνe−hν0e
From graph, threshold frequency of A is less
than that of B.
So, as work function = hν0
Where h=Planck′sConstant
So, work function of A is less than B.
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