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Question

The stopping potential as function of frequency of incident radiation is plotted for two different photoelectric surfaces A and B. The graphs show that the work function of A is
596932.jpg
  1. greater than that of B
  2. lesser than that of B
  3. equal than that of B
  4. no comparison

A
lesser than that of B
B
equal than that of B
C
no comparison
D
greater than that of B
Solution
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From Einstein’s equation ,

eV0=hνhν0

V0=hνehν0e

From graph, threshold frequency of A is less than that of B.

So, as work function = hν0

Where h=PlancksConstant

So, work function of A is less than B.

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