Question

The stopping potential as function of frequency of incident radiation is plotted for two different photoelectric surfaces A and B. The graphs show that the work function of A is

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A

greater than that of B

B

lesser than that of B

C

equal than that of B

D

no comparison

Medium

Solution

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Correct option is B)

From Einstein’s equation ,

From graph, threshold frequency of A is less than that of B.

So, as work function =

Where

So, work function of A is less than B.

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