The velocity of a particle that executes S.H.M. is at its mean position 0.866 m/s.Velocity at a displacement half of its amplitude from mean position is
0.5ms−1
1 ms−1
1.414ms−1
0.75ms−1
A
0.75ms−1
B
1 ms−1
C
0.5ms−1
D
1.414ms−1
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Solution
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vmax=Aω=0.866ms At x=A2;v=ω√A2−x2 v=√32ωA=√32vmax v=√32×0.866=0.75ms
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