Question

The wavelength associated with a photon of energy 3.31 eV is nearly

• A. 4000 $A^o$
• B. 3750 $A^o$
• C. 5000 $A^o$
• D. 400 $A^o$

Answer 1

Answer: (B)

$Energy=\frac{hc}{\lambda }$

$\lambda =\frac{hc}{energy}$

$=\frac{1240}{3.31}(hc=1240eV)$

$=375nm$
$=3750A^o$
So, the answer is option (B).