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Physics

Einstein's Photoelectric Equation : Energy Quantum of Radiation

Question

The work function of the metal, if the kinetic energies of the photoelectrons are $$E_{1}$$ and $$E_{2}$$, with wavelengths of incident light $$\lambda_{1}$$ and $$\lambda_{2}$$, is

$$\dfrac {E_{1}E_{2}}{\lambda_{2} - \lambda_{1}}$$

$$\dfrac {\lambda_{1}\lambda_{2}E_{1}}{(\lambda_{1} - \lambda_{2})E_{2}}$$

$$\dfrac {E_{1}\lambda_{1} - E_{2}\lambda_{2}}{\lambda_{2} - \lambda_{1}}$$

$$\dfrac {(E_{1} - E_{2})\lambda_{1}\lambda_{2}}{(\lambda_{1} - \lambda_{2})}$$

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Solution

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Correct option is A. $$\dfrac {E_{1}\lambda_{1} - E_{2}\lambda_{2}}{\lambda_{2} - \lambda_{1}}$$

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