The work of tungsten is 4-50 eV- The wavelength of fastest electron emitted when light whose photon energy is 5-50 eV falls on tungsten surface- is-12-27overset-o-A-0-286overset-o-A-12400overset-o-A-1-227overset-o-A-

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E-5-5eV-x3D5-4-5eVK-E-E-x2212-x3D5-5-5-x2212-4-5-1eV-x3BB- 6-6-xD7-1034-x221A-2-xD7-9-1-xD7-10-x2212-31-xD7-1-xD7-1-16-xD7-10-x2212-191-24-xD7-109m-1-24oA

The work function of tungsten is $4.50$ eV. The wavelength of fastest electron emitted when light whose photon energy is $5.50$ eV falls on tungsten surface, is?
$12.27 o A$
$0.286 o A$
$12400 o A$
$1.227 o A$

$E = 5.5 e V$
$ϕ = 4.5 e V$
$K . E = E - ϕ = 5.5 - 4.5 = 1 e V$
$λ$ = $\frac{6.6 \times 10^{34}}{\sqrt{2 \times 9.1 \times 10^{- 31} \times 1 \times 1.16 \times 1 0^{- 19}}}$
$1.24 \times 10^{9} m = 1.24 o A$

The work function of tungsten is 4.50 eV. The wavelength of fastest electron emitted when light whose photon energy is 5.50 eV falls on tungsten surface, is?12.27oA0.286oA12400oA1.227oA

E=5.5eVϕ=4.5eVK.E=E−ϕ=5.5−4.5=1eVλ= 6.6×1034√2×9.1×10−31×1×1.16×10−191.24×109m=1.24oA

The work function of tungsten is $4.50$ eV. The wavelength of fastest electron emitted when light whose photon energy is $5.50$ eV falls on tungsten surface, is?
$12.27 o A$
$0.286 o A$
$12400 o A$
$1.227 o A$

$E = 5.5 e V$
$ϕ = 4.5 e V$
$K . E = E - ϕ = 5.5 - 4.5 = 1 e V$
$λ$ = $\frac{6.6 \times 10^{34}}{\sqrt{2 \times 9.1 \times 10^{- 31} \times 1 \times 1.16 \times 1 0^{- 19}}}$
$1.24 \times 10^{9} m = 1.24 o A$