λ0=12375W0
The maximum wavelength of light required for the photoelectric emission for Lithium, λLi=123752.3=5380˙A
Similarly for Copper, λCu=123754=3094˙A
Since the wavelength 3094˙A does not lie in the visible region, but it is in the ultraviolet region so copper can't be used to work with visible light. Hence to work with visible light, lithium metal will be used for the as photoelectric cell as λLi lies in visible region.