Threshold wavelength a metal is 5675 mathring A - Find out the work of the metal- -h - 6-63 times 10-34- -J-s-

Question

Threshold wavelength a metal is  5675 mathring A - Find out the work of the metal-  -h - 6-63 times 10-34- -J-s-

Toppr Admin · Accepted Answer

Work function of metal - -phi-0 - hv-0 -160- - -dfrac-hc-lambda-0- - Joule - - -dfrac-hc-e -lambda-0- -eV -160- - -dfrac-6-63 -times 10-34- -times 3 -times 10-8-5675 -times 10-10- -times 1-6 -times 10-19- -160- - 2-19 -eV - 2-2 -eV -160-

Threshold wavelength for a metal is $$ 5675 \mathring A $$. Find out the work function of the metal. $$ (h = 6.63 \times 10^{-34} \,J-s)$$

Work function of metal $$ \phi_0 = hv_0 $$
$$ = \dfrac{hc}{\lambda_0} $$ Joule $$ = \dfrac{hc}{e \lambda_0} \,eV $$

$$ = \dfrac{6.63 \times 10^{-34} \times 3 \times 10^8}{5675 \times 10^{-10} \times 1.6 \times 10^{-19}} $$

$$ = 2.19 \,eV = 2.2 \,eV $$

Threshold wavelength for a metal is $$ 5675 \mathring A $$. Find out the work function of the metal. $$ (h = 6.63 \times 10^{-34} \,J-s)$$

Work function of metal $$ \phi_0 = hv_0 $$ $$ = \dfrac{hc}{\lambda_0} $$ Joule $$ = \dfrac{hc}{e \lambda_0} \,eV $$ $$ = \dfrac{6.63 \times 10^{-34} \times 3 \times 10^8}{5675 \times 10^{-10} \times 1.6 \times 10^{-19}} $$ $$ = 2.19 \,eV = 2.2 \,eV $$

Work function of metal $$ \phi_0 = hv_0 $$
$$ = \dfrac{hc}{\lambda_0} $$ Joule $$ = \dfrac{hc}{e \lambda_0} \,eV $$

$$ = \dfrac{6.63 \times 10^{-34} \times 3 \times 10^8}{5675 \times 10^{-10} \times 1.6 \times 10^{-19}} $$

$$ = 2.19 \,eV = 2.2 \,eV $$