Two deuterons undergo nuclear fusion to form a Helium nucleus. Energy released in this process is : (given binding energy per nucleon for deuteron =1.1MeV and for helium =7.0MeV)
30.2MeV
23.6MeV
25.8MeV
32.4MeV
A
23.6MeV
B
25.8MeV
C
32.4MeV
D
30.2MeV
Open in App
Solution
Verified by Toppr
21H+21H→42He+Energy
Mass of deuterium =2.013550
Mass of He =4.013490
The energy released in the process is :
ΔE=4.002602×7MeV−2×2.01355×1.1MeV
ΔE=23.588MeV
Was this answer helpful?
10
Similar Questions
Q1
Two deuterons undergo nuclear fusion to form a Helium nucleus. Energy released in this process is : (given binding energy per nucleon for deuteron =1.1MeV and for helium =7.0MeV)
View Solution
Q2
The binding energy per nucleon of deuteron (1H2) and helium (2He4) are 1.1MeV and 7.0MeV, respectively. The energy released when two deuterons fuse to form a helium nucleus is
View Solution
Q3
Two deuterons undergo nuclear fusion to form a Helium nucleus. Energy released in this process is :
View Solution
Q4
The binding energy per nucleon of a Deuteron (21H) and helium nucleus (42He) is 1.1MeV and 7MeV respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is :
View Solution
Q5
The binding energy per nucleon in deuterium and helium nuclei are 1.1MeV and 7.0MeV, respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is :