Two identical photo cathodes receive light of frequencies f1 and f2. if the velocities of the photoelectrons (of mass 'm') coming out are respectively v1 and v2, then:
v21−v22=2hm(f1−f2)
v1+v2=[2hm(f1+f2)]1/2
v21+v22=2hm(f1+f2)
v1−v2=[2hm(f1−f2)]1/2
A
v21−v22=2hm(f1−f2)
B
v1+v2=[2hm(f1+f2)]1/2
C
v21+v22=2hm(f1+f2)
D
v1−v2=[2hm(f1−f2)]1/2
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