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Photons and Photoelectric Effect

Question

Ultraviolet light of wavelength $$66.26\ nm$$ and intensity $$2\ W/m^{2}$$ falls on potassium surface by which photoelectrons are ejected out. If only $$0.1\%$$ of the incident photons produce photoelectrons, and surface area of metal surface is $$4\ m^{2}$$, how many electrons are emitted per second?

A

$$3\times 10^{15}$$

B

$$2.67\times 10^{15}$$

C

$$4.17\times 10^{16}$$

D

$$3.33\times 10^{17}$$

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Solution

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Correct option is A. $$2.67\times 10^{15}$$

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