Let the velocity of electron is v , so when there is no deflection
evB=eE→ev×2×10−3=e×2×103
v=106 , distance to screen to 20 cm or 0.2m
so time taken to strike the screen t= 0.2106sec
let the electric field on y plate be E
so acceleration on electron a=eEme
now using S=at2/2, S= 2cm
we get E=5.68V/m
V=.02×5.68=0.11V
So, the answer is option (A).