Question

When a surface is irradiated with light of wavelength , a photocurrent appears which vanishes if a retarding potential greater than is applied across the phototube. When different source of light is used, it is found that the critical retarding potential is changed to . Find the work function of the emitted surface and the wavelength of the second source. 

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Solution

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Given, wavelength of light used,
Stopping potential, $$V_{o} =0.6V$$
According to Einstein potential equation we have;
........ (1)
ie,
Where, = work function 
  = stopping potential 
For the first source 
Putting these values in equation (1), we get 

Let be the wavelength of the second source. 
Stopping potential   =1.1 v (given) 
Therefore, 

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