Which metal-s- can be used to produce electrons by the photoelectric effect from given of light -Barium onlyLithium- tantalum or tungstenTungsten or tantalumBarium or lithium

Photoelectric effectKEmax-hv-x2212-WoThe minimum energy to knock out electronsKE-x2265-0hv-gt-Wohc-x3BB-gt-Wo -1-Here- available energy - E-hc-x3BB-2-75eVFor Photoelectric effectWo-lt-2-75eV by -xA0- -1-From the table- only true for Ba and Li

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Standard XII

Physics

Work Function

Question

Which metal(s) can be used to produce electrons by the photoelectric effect from given source of light ?
Barium only
Lithium, tantalum or tungsten
Tungsten or tantalum
Barium or lithium

Barium or lithium

Barium only

Tungsten or tantalum

Lithium, tantalum or tungsten

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Solution

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Photoelectric effect
$K E_{m a x} = h v - W_{o}$
The minimum energy to knock out electrons
$K E \geq 0$
$h v > W_{o}$
$\frac{h c}{λ} > W_{o}$ ------------------(1)
Here, available energy = $E = \frac{h c}{λ} = 2.75 e V$
For Photoelectric effect
$W_{o} < 2.75 e V$ by (1)
From the table, only true for Ba and Li

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Which metal(s) can be used to produce electrons by the photoelectric effect from given source of light ?Barium onlyLithium, tantalum or tungstenTungsten or tantalumBarium or lithium

Photoelectric effectKEmax=hv−WoThe minimum energy to knock out electronsKE≥0hv>Wohcλ>Wo ------------------(1)Here, available energy = E=hcλ=2.75eVFor Photoelectric effectWo<2.75eV by (1)From the table, only true for Ba and Li

Which metal(s) can be used to produce electrons by the photoelectric effect from given source of light ?
Barium only
Lithium, tantalum or tungsten
Tungsten or tantalum
Barium or lithium