With the decrease in the wave length of the incident radiation the velocity of the photoelectrons emitted from a given metal
Remains same
Decreases
Increases first and then decreases
Increases
A
Remains same
B
Increases
C
Decreases
D
Increases first and then decreases
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Solution
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As wavelength decrease , frequency increases and hence K.E of photoelectrons increases , thereby increasing the velocity.
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