A parallel plate air capacitor has a capacitance C. When it is half filled with a dielectric of dielectric constant 5, the percentage increase in the capacitance will be:
400%
66.6%
33.3%
200%
A
200%
B
400%
C
33.3%
D
66.6%
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Solution
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C=Aϵ0dC1=KC=5C=Aϵ0Kd%increase=(5C−CC)×100=400%
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