A short bar magnet of magnetic moment 0.4JT1 is placed in a uniform magnetic field of 0.16 T. The magnet is in stable equilibrium when the potential energy is
-0.064 J
0.082 J
zero
0.064 J
A
zero
B
0.082 J
C
0.064 J
D
-0.064 J
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Solution
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Potential energy of a magnet with magnetic moment →M placed in a magnetic field →B is given by
U=−→M.vecB
=−MBcosθ
which is smallest for θ=0
Hence Umin=−MB=−0.4×0.16J
=−0.064J
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