A square wire of side 3.0cm is placed 25cm away from a concave mirror of focal length 10cm. Find area enclosed by the image of the wire in cm2. The centre of the wire is on the axis of the mirror, with the all sides normal to the axis.
1f=1u+1v
1v=1−10−1−25=−350
v=−503
m=h′h=−vu
h is the height of the object
h′3=−(−503)−25 h=−2cm
=(−2cm)2=4cm2 so the area enclosed by image of wire.