Potential difference between two points ΔV= work done per unit charge=∫→F.→drq=∫q→E.→drq
ΔV=−∫→E.→dr ...(i)
E=25^i+30^j and coordinates of given point →r=2^i+2^j→dr=dx^i+dy^j substituting values in equation (i)
ΔV=−∫→r→025^i+30^j.dx^i+dy^j
ΔV=−∫2025dx+∫2030dy
=[25x]20+[[30y]20
=50+60=−110V
V−Vorigin=−110J given Vorigin=0
V=−110J hence correct answer is option A