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Standard IX
Mathematics
Question
Expand:
[
3
2
x
+
1
]
3
Open in App
Solution
Verified by Toppr
[
3
2
x
+
1
]
3
∴
(
x
+
y
)
3
=
x
3
+
y
3
+
3
x
2
y
+
3
x
y
2
⇒
(
3
2
x
)
3
+
(
1
)
3
+
3
×
(
3
2
x
)
2
×
1
+
3
×
(
3
2
x
)
×
(
1
)
2
⇒
27
8
x
3
+
1
+
3
×
9
4
x
2
+
3
×
3
2
x
×
1
⇒
27
8
x
3
+
1
+
27
4
x
2
+
9
2
x
⇒
27
8
x
3
+
27
4
x
2
+
9
2
x
+
1
Ans
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