Find the number whose double is 45 greater then its half-

Question

Toppr Admin · Accepted Answer

Let the number be xGiven the double of the number is 45 greather than its half-x27F9-2x-45-x2-x27F9-2x-x2212-x2-45-x27F9-3x2-45-x27F9-x-30So the number is 30

Find the number whose double is $45$ greater then its half.

Let the number be $x$
Given the double of the number is $45$ greather than its half
$⟹ 2 x = 45 + \frac{x}{2}$
$⟹ 2 x - \frac{x}{2} = 45$
$⟹ \frac{3 x}{2} = 45$
$⟹ x = 30$
So the number is $30$

Find the number whose double is 45 greater then its half.

Let the number be xGiven the double of the number is 45 greather than its half⟹2x=45+x2⟹2x−x2=45⟹3x2=45⟹x=30So the number is 30

Find the number whose double is $45$ greater then its half.

Let the number be $x$
Given the double of the number is $45$ greather than its half
$⟹ 2 x = 45 + \frac{x}{2}$
$⟹ 2 x - \frac{x}{2} = 45$
$⟹ \frac{3 x}{2} = 45$
$⟹ x = 30$
So the number is $30$