For a prism kept in air, it is found that for an angle of incidence 60∘, the angle of refraction ′A′, angle of deviation ′δ′, and angle of emergence ′e′ become equal. The minimum angle of incidence of a ray that will be transmitted through the prism is
1.15
1.5
1.33
1.73
A
1.33
B
1.15
C
1.73
D
1.5
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Solution
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Given i=60∘,A=δ=e δ=i+e−A⇒δ=1 (∵e=A) and (δ=i=e μ=sin(A+δm2)sinA2 Here, angle of deviation is minimum (∵i=e) μ=sin(60∘+60∘2)sin(60∘/2)=√3.
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