If for all x different from both 1 and 0 we have f1(x)=xx−1,f2(x)=11−x, and for all integers n≥1, we have fn+2(x)={fn+1(f1(x))ifnisoddfn+1(f2(x))ifniseven then f4 equals
x
x−1
f1(x)
f2(x)
A
f1(x)
B
f2(x)
C
x−1
D
x
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