It is given that $$\angle 1={120}^{o}$$
from the figure we know that $$\angle 1$$ and $$\angle 2$$ form a linear pair of angles
so it can be written as
$$\angle 1+\angle 2={ 180 }^{ o }$$
by substituting the values
$${120}^{o}+\angle 2={ 180 }^{ o }$$
$$\angle 2={60}^{o}$$
from the figure we know that $$\angle 1$$ and $$\angle 3$$ are vertically opposite angles
we get
$$\angle 1=\angle 3={120}^{o}$$
from the figure we know that $$\angle 2$$ and $$\angle 4$$ are vertically opposite angles
we get
$$\angle 2=\angle 4={60}^{o}$$
it is given that $$l\parallel m$$ and $$t$$ is a transversal
so the corresponding angles according to the figures is written as
$$\angle 1=\angle 5={120}^{o}$$
$$\angle 2=\angle 6={60}^{o}$$
$$\angle 3=\angle 7={120}^{o}$$
$$\angle 4=\angle 8={60}^{o}$$