The de-Broglie wavelength of a particle moving with a velocity 2.25×108m/s is equal to the wavelength of photon. The ratio of kinetic energy of the particle to the energy of the photon is :
18
38
58
78
A
18
B
78
C
38
D
58
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Solution
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Kparticle=12mv2 also λ=hmv
⇒Kparticle=12(hλv).v2=vh2λ ...(i)
Kphoton=hcλ ....(ii)
∴KparticleKphoton=v2c=2.25×1082×3×108=38
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