Figure shows lines of force for a system of two point charges. The possible choice for the charges is:
q1=4μC,q2=−1.0μC
q1=1μC,q2=−4μC
q1=−2μC,q2=+4μC
q1=3μC,q2=2μC
A
q1=−2μC,q2=+4μC
B
q1=4μC,q2=−1.0μC
C
q1=1μC,q2=−4μC
D
q1=3μC,q2=2μC
Open in App
Solution
Verified by Toppr
As lines of forces are coming out of q1 and going into q2
q1→ positive charge
q2→ negative charge
As number of lines of forces are greater near q1, then:
∣q1∣>∣q2∣
∴ option A is correct.
Was this answer helpful?
4
Similar Questions
Q1
Four charges q1=1μC, q2=2μC, q3=3μC and q4=4μC are placed at (0,0,0), (1m,0,0), (0,1m,0), (0,0,1m) respectively. Let →Fi be the net force acting on ith charge of the given charges then ∑→Fi=....
View Solution
Q2
If Q1=5μC, Q2=3μC and Q3=−2μC, then the net charge in the system is :
View Solution
Q3
Three charges q1=1μC,q2=−2μC,q3=2μC, are placed at the vertices of an equilateral triangle of side 1m. The magnitude of net electric force in newton on charge q1 is
View Solution
Q4
Point charges q1 and q2 are placed in air at a distance 'r'. The ratio of the force on charge q1 by charge q2 and force on charge q2 by charge q1 is?
View Solution
Q5
Two charges Q1=18μC and Q2=−2μC are separated by a distance R, and Q1 is on the left of Q2. The distance of the point where the net electric field is zero is :