Find the sum:
$$\dfrac{-3}{11}+\dfrac{5}{9}$$
The sum of $$-\dfrac{3}{11}$$ and $$\dfrac{5}{9}$$ is $$-\dfrac{3}{11}+\dfrac{5}{9}$$
$$=-\dfrac{3\times 9}{11\times 9}+\dfrac{5\times 11}{9\times 11}$$
$$=-\dfrac{27}{99}+\dfrac{55}{99}$$
$$=\dfrac{-27+55}{99}$$
$$=\dfrac{28}{99}$$