If Planck’s constant is denoted by h and electronic charge by e, then photoelectric effect allows determination of:
Only e
Both h and e
Only h/e
Only h
A
Only h
B
Both h and e
C
Only h/e
D
Only e
Open in App
Solution
Verified by Toppr
The correct option is D Only h/e In photoelectric effect we can know only the stopping potential. Stopping potential =(hcλ−ϕ)/e =hceλ−ϕ/e So, we can determine only h/e because we know stopping potential, frequency and work function of the metal.
Was this answer helpful?
0
Similar Questions
Q1
If Planck’s constant is denoted by h and electronic charge by e, then photoelectric effect allows determination of:
View Solution
Q2
Assertion (A): H2S acts only as reducing agent.
Reason (R): H2S is a dibasic acid.
View Solution
Q3
H2S acts only as a reducing agent while SO2 can act both as a reducing and oxidizing agent because
View Solution
Q4
Assertion :H2O2 acts only as an oxidising agent. H2O2⟶H2O+O Reason: All peroxides behaves as oxidising agents only.
View Solution
Q5
A 50 litre vessel is equally divided into three parts with the help of two stationary semi permeable membrane(SPM). The vessel contains 60g H2 gas in the left chamber, 160g O2 in the middle and 140g N2 in the right one. The left SPM allows transfer of only H2 gas while the right one allows the transfer of both H2 andN2. The final ratio of pressure in the three chambers: