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Standard XII
Physics
Dimensional Analysis
Question
The dimensional formula of Planck's constant is:
[
M
L
2
T
−
1
]
[
M
L
2
T
−
2
]
[
M
L
T
2
]
[
M
L
0
T
2
]
A
[
M
L
2
T
−
1
]
B
[
M
L
T
2
]
C
[
M
L
2
T
−
2
]
D
[
M
L
0
T
2
]
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Solution
Verified by Toppr
Energy of photon is given as
E
=
h
ν
⟹
h
=
E
ν
Dimension of
E
=
[
M
L
2
T
−
2
]
Dimension of
ν
is
[
T
−
1
]
Thus the dimension of plank's constant
h
is
[
M
L
2
T
−
1
]
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