Solve
Guides
Join / Login
Use app
Login
0
You visited us
0
times! Enjoying our articles?
Unlock Full Access!
Standard XII
Chemistry
Question
The normality of solution obtained by mixing
100
m
L
of 0.2 M
H
2
S
O
4
with
100
m
L
of 0.2 M
N
a
O
H
is:
0.2
0.5
0.1
0.3
A
0.2
B
0.3
C
0.1
D
0.5
Open in App
Solution
Verified by Toppr
Normality= Molarity
×
Valency factor
.
.
.
.
.
.
.
.
.
.
(
1
)
Valency factor for
H
2
S
O
4
=
2
and that of
N
a
O
H
=
1
∴
N
1
of
H
2
S
O
4
=
0.2
×
2
=
0.4
N
2
of
N
a
O
H
=
0.2
×
1
=
0.2
We have,
N
1
V
1
+
N
2
V
2
=
N
R
V
R
⟶
(
2
)
V
R
=
100
+
100
=
200
∴
b
y
e
q
u
a
t
i
o
n
(
2
)
,
w
e
g
e
t
,
0.4
(
100
)
+
0.2
(
100
)
=
N
R
(
200
)
∴
40
−
20
=
N
R
×
200
∴
Normality of resultant solution
N
R
=
0.1
Hence, the correct option is
A
Was this answer helpful?
18
Similar Questions
Q1
The normality of solution obtained by mixing
100
m
L
of 0.2 M
H
2
S
O
4
with
100
m
L
of 0.2 M
N
a
O
H
is:
View Solution
Q2
What will be the normality of the solution obtained by mixing
100
m
L
of
0.2
M
H
2
S
O
4
with
100
m
L
of
0.2
M
N
a
O
H
?
View Solution
Q3
The normality of mixture obtained by mixing 100 ml of
0.2
M
H
2
S
O
4
+
100
m
l
of 0.2 M NaOH is:
View Solution
Q4
The normality of solution obtained by mixing
100
mL
of
0.2
M
H
2
S
O
4
with
100
mL
of
0.2
M
N
a
O
H
is:
View Solution
Q5
What will be the normality of the solution obtained by mixing
50
m
L
of
0.2
M
H
2
S
O
4
with
50
m
L
of
0.1
N
C
a
(
O
H
)
2
?
View Solution