The rate constant for the forward and backward reactions of hydrolysis of ester are 1.1×10−2 and 1.5×10−3 respectively. The equilibrium constant of the following reaction is:
CH3COOC2H5+H+⇌CH3COOH+C2H5OH
7.75
6.33
7.33
8.33
A
6.33
B
7.75
C
7.33
D
8.33
Open in App
Solution
Verified by Toppr
Rate of forward reaction =1.1×10−2[CH3COOC2H5][H+] Rate of backward reaction =1.5×10−3[CH3COOH][C2H5OH]
Was this answer helpful?
1
Similar Questions
Q1
The rate constant for the forward and backward reactions of hydrolysis of ester are 1.1×10−2 and 1.5×10−3 respectively. The equilibrium constant of the following reaction is:
CH3COOC2H5+H+⇌CH3COOH+C2H5OH
View Solution
Q2
The rate constant for forward reaction and backward reaction of hydrolysis of ester are 1.1×10−2 and 1.5×10−3 per minute respectively. Equilibrium constant for the reaction is : CH3COOC2H5+H2O⇌CH3COOH+C2H5OH
View Solution
Q3
The rate constant for forward and backward reaction of hydrolysis of ester are 1.1×10−2 and 1.5×10−3 per minute respectively.
Equilibrium constant for the reaction is :
CH3COOC2H5+H2O⇌CH3COOH+C2H5OH
View Solution
Q4
The rate constant for the forward and backward reactions of the hydrolysis of ester are 1.1×10−2 and 1.5×10−3 min-1 respectively. The equilibrium constant of the reaction is:
View Solution
Q5
The rate constant for forward and backward reaction of hydrolysis of ester are 1.1×10−2 and 1.5×10−3per minute respectively. Equilibrium constant for the reaction is?