What length of tarpaulin 3 m wide will be required to make a conical tent of height 8 m and base radius 6 m? Assume that extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm (use π=3.14)
Curved surface area of tent =πrl
r=6m, h=8m
We know that
l=√82+62
l=√100
l=10 m
Curved surface area of tent =3.14×6×10
=188.4 m2
Now,
Area of tarpaulin material = Area of tent
L×B=188.4
L×3=188.4
L=188.43
L=62.8 m
Now, given that margin is 20 cm
Total length = Length + Margin
=62.8+20×1100
=62.8+0.2
=63 m