0.3kg of steam at 1000C is mixed with 6kg of water. After the steam condenses the temperature of the mixture rises to 400C. The initial temperature of the water is:
700C
300C
400C
100C
A
300C
B
400C
C
700C
D
100C
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Solution
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Heat released by steam on condesation is Q1=0.3×2260×103J ; where, Latent heat of condensation of steam is : 2260×103J/kgoC
Let the initial temperature of water be T.
Balancing the energy released and absorbed,
Q1+0.3×4200×(100−40)=6×4200×(40−T) ; where spceific heat of water is: 4200J/kgoC
So, 40−T≈30⇒T=10oC
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