A cone of base radius R and height h is located in a uniform electric field →E parallel to its base. The electric flux entering the cone is:
4EhR
2EhR
12EhR
EhR
A
12EhR
B
2EhR
C
4EhR
D
EhR
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Solution
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We know that, ϕ=E.ACosθ Flux crossing through the area of cone parallel to the electric field which is nothing but a right angle triangle having base 2R and height h therefore, ϕ=EhR
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