Solve
Study
Textbooks
Guides
Use app
Login
>>
Class 11
>>
Chemistry
>>
Thermodynamics
>>
Spontaneity
>>
Calculate the entropy change in surround
Question
Calculate the entropy change in surroundings when 1.00 mol of
H
2
O
(
l
)
is formed under standard conditions at 298 K. Given
Δ
r
H
0
= - 286 kJ
m
o
l
−
1
.
Hard
Open in App
Updated on : 2022-09-05
Solution
Verified by Toppr
H
2
(
g
)
+
2
1
O
2
(
g
)
⟶
H
2
O
(
l
)
Δ
f
H
0
=
−
2
8
6
K
J
/
m
o
l
From the above equation,
At
2
9
8
K
, when
1
mole of
H
2
O
(
l
)
is formed,
2
8
6
K
J
of heat is released. The same amount of heat is absorbed by the surroundings.
∴
q
s
u
r
r
.
=
+
2
8
6
K
J
/
m
o
l
;
T
=
2
9
8
K
As we know that,
Δ
S
s
u
r
r
.
=
T
q
s
u
r
r
.
∴
Δ
S
s
u
r
r
.
=
2
9
8
2
8
6
=
0
.
9
6
K
J
/
m
o
l
−
K
Hence the entropy change in surroundings will be
0
.
9
6
K
J
/
m
o
l
.
Solve any question of
Chemical Thermodynamics
with:-
Patterns of problems
>
Was this answer helpful?
0
0
Similar questions
Calculate the entropy change for the following reaction,
H
2
(
g
)
+
C
l
2
(
g
)
⟶
2
H
C
l
(
g
)
at
2
9
8
K
. Given that,
S
H
2
⊖
=
1
3
1
J
K
−
1
m
o
l
−
1
,
S
C
l
2
⊖
=
2
2
3
J
K
−
1
m
o
l
−
1
and
S
H
C
l
⊖
=
1
8
7
J
K
−
1
m
o
l
−
1
.
Hard
View solution
>
The equilibrium constant for the reaction given below is
2
.
0
×
1
0
−
7
at
3
0
0
K. Calculate the standard entropy change for the reaction.
(
Δ
H
0
=
2
8
.
4
k
J
m
o
l
−
1
)
P
C
l
5
(
g
)
⇌
P
C
l
3
(
g
)
+
C
l
2
(
g
)
Hard
View solution
>
Calculate the entropy change for the conversion of
1
g
ice to water at
2
7
3
K
.[
Δ
H
f
u
s
i
o
n
=
6
.
0
2
5
k
J
m
o
l
−
1
]
Hard
View solution
>
Calculate the entropy change
(
J
/
m
o
l
K
)
of the given reaction. The molar entropies
(
J
/
K
−
m
o
l
)
are given in brackets after each substance
2
P
b
S
(
s
)
[
9
1
.
2
]
+
3
O
2
(
g
)
[
2
0
5
.
1
]
→
2
P
b
O
(
s
)
[
6
6
.
5
]
+
2
S
O
2
(
g
)
[
2
4
8
.
2
]
Hard
View solution
>
Calculate the entropy change in surroundings when 1.00 mol of
H
2
O
(l) is formed under standard conditions at 298k,
Given
△
,
H
o
=
−
2
8
6
k
J
m
o
l
−
1
Medium
View solution
>
More From Chapter
Thermodynamics
View chapter
>
Revise with Concepts
Spontaneity
Example
Definitions
Formulaes
>
Entropy and Spontaneity
Example
Definitions
Formulaes
>
Gibbs Energy and Spontaneity
Example
Definitions
Formulaes
>
Third Law of Thermodynamics
Example
Definitions
Formulaes
>
View more
Learn with Videos
Spontaneous Processes
12 mins
Introduction to Entropy
20 mins
Sponteniety in Terms of Entropy
14 mins
Spontaneity in Terms of Gibbs Free Energy
7 mins
Third Law of Thermodynamics
8 mins
Shortcuts & Tips
Common Misconceptions
>
Mindmap
>
Problem solving tips
>
Important Diagrams
>
Cheatsheets
>
Practice more questions
JEE Mains Questions
1 Qs
>
JEE Advanced Questions
1 Qs
>
Easy Questions
34 Qs
>
Medium Questions
455 Qs
>
Hard Questions
498 Qs
>