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Standard XI
Mathematics
NCERT
Question
Find the equation of the circle with centre
(
1
,
1
)
and radius
√
2
Open in App
Solution
Verified by Toppr
Here it is given that centre
(
h
,
k
)
=
(
1
,
1
)
and radius
r
=
√
2
Therefore the equation of the circle is
(
x
−
1
)
2
+
(
y
−
1
)
2
=
(
√
2
)
2
⇒
x
2
−
2
x
+
1
+
y
2
−
2
y
+
1
=
2
⇒
x
2
+
y
2
−
2
x
−
2
y
=
0
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