Find the sum of
$$-51, \,-203, \,36$$ and $$-28$$
$$-51+(-203)+36+(-28)$$
$$=[-51+(-203)]+[36+(-28)]$$
Here, we will $$1^{st}$$ solve square bracket
$$\therefore [-51+(-203)]+[36+(-28)]=(-51-203)+(36-28)$$
$$=-254+8$$
$$=-246$$
$$-246$$ is the sum of $$-51, \,-203, \,36$$ and $$-28$$