Solve
Guides
0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

For an npn transistor R. = 1.2 x 10$S2, R = 6000 12, B = 50. It is connected to amplify an input signal in active mode in common emitter configuration. The input signal is : out lm V -1mV he output signal looks like. IV 0.5V 0.511. 0.5V (D) -0.5V +0.5V - 1 nc...dhia

Open in App
Solution
Verified by Toppr


Was this answer helpful?
0
Similar Questions
Q1
Reason
In common emitter mode the input signal is connected in series with the voltage applied to the base emitter function.
Assertion
In transistor common emitter mode as an amplifier is preferred over common base mode.
View Solution
Q2
A transistor is used in the common emitter mode as an amplifier then:
(A) the base emitter junction is forward baised.
(B) the base emitter junction is reverse baised.
(C) the input signal is connected in series with the voltage applied to bias the base emitter junction.
(D) the input signal is connected in series with the voltage applied to bias the base collector junction.
View Solution
Q3

In the common-emitter transistor input signal is between


View Solution
Q4
An NPN transistor is used in common emitter configuration as an amplifier with 1 kΩ load resistance. Signal voltage of 10 mV is applied across the base-emitter. This produces a 3 mA change in the collector current and 15 μA change in the base current of the amplifier. The input resistance and voltage gain are
View Solution
Q5
In transistors (working as amplifiers), having common base npn configuration, when we give positive half cycle of input a.c signal voltage, then it opposes the forward biasing of the emitter base circuit and vice versa. Why?
View Solution