In isosceles triangle ABC, AB = AC. The side BA is produced to D such that BA = AD. Is ∠BCD=90∘. ? If true then enter 1 else if False enter 0
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In triangle ABC, AB = AC, so , ∠ABC=∠ACB Now, since, AB =AD then, AC = AD hence, ∠ACD=∠ADC Now, let ∠ABC=∠ACB=x and ∠ACD=∠ADC=y so, ∠ABC+∠BCD+∠BDC=180 ∠ABC+∠ACB+∠ACD+∠BDC=180 x+x+y+y=180 2(x+y)=180 x+y=90 ∠ACB+∠ACD=90 ∠BCD=90
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