No- of angular nodes and total nodes 2p orbital will be -1- 0-2 -2- 1-2 -3- 1-1 -4- 0-1

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No. of angular nodes and total nodes for 2p orbital will be (1) 0,2 (2) 1,2 (3) 1,1 (4) 0,1

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Reason
Electronic configuration of oxygen atom is $$1s^{2}\ 2s^{2}\ 2p^{4}$$. The number of radial and angular nodes for an orbital is $$(n-l-1)$$ and $$l$$, respectively.
Assertion
Sum of the radial and angular nodes of all the occupied orbitals in ground state of oxygen atom is $$4$$.
Sum of the radial and angular nodes of all the occupied orbitals in ground state of oxygen atom is $$4$$.

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