Prove that the quadrilateral formed by joining the mid-points of the consecutive sides of a rectangle is a rhombus.
Length=l
Breadth=b
Let the diagonal intersect each other at O
As it can be seen from imageSide EH=EF=FG=GH=√l2+b22
Hence are all sides are congruent
Also, EO=OG=b2
HO=OF=l2
Hence the diagonal bisect each other.
And as it can be seen from the figure that they intersect at 90∘
Hence, due to all the reasons above it is a proved that the quadilateral formed is rhombus