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Standard XII
Chemistry
Heat of Formation
Question
The bond dissociation energy of gaseous
H
2
,
C
l
2
and
H
C
l
are
104
,
58
and
103
kcal
m
o
l
−
1
respectively. The enthalpy formation for
H
C
l
gas will be:
22.0
kcal
44.0
kcal
−
22.0
kcal
−
44.0
kcal
A
−
22.0
kcal
B
22.0
kcal
C
−
44.0
kcal
D
44.0
kcal
Open in App
Solution
Verified by Toppr
1
2
H
2
+
1
2
C
l
2
→
H
C
l
Δ
f
H
(
H
C
l
)
=
Δ
H
(
Rea
)
−
Δ
H
(
Pro
)
Implies that
=
1
2
(
104
)
+
1
2
(
58
)
−
103
=
−
22
k
c
a
l
.
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3
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