Using the standard electrode potentials given in Table 3.1, predict if the reaction between the following is feasible:
(i) Fe3+(aq) and I−(aq)
(ii) Ag+(aq) and Cu(s)
(iii) Fe3+(aq) and Br−(aq)
(iv) Ag(s) and Fe3+(aq)
(v) Br2(aq) and Fe2+(aq)
(i) When emf is positive, the reaction is feasible.
Eocell=EoFe−E0I2=0.77−0.54=0.23V
Reaction is feasible.
(ii) Eocell=EoAg−EoCu=0.80−0.34=0.46V
Reaction is feasible.
(iii) Eocell=EoFe−E0Br2=0.77−1.09=−0.32 V
Reaction is not feasible.
(iv) Eocell=EoFe−E0Ag=0.77−0.80=−0.03 V
Reaction is not feasible.
(v) Eocell=EoBr2−E0Fe=1.09−0.77=0.32 V
Reaction is feasible.