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Standard XII
Biology
Question

A yellow round seeded Pea plant is crossed with green wrinkled seeded Pea plant. Four phenotypes appeared in the progeny in the ratio of 1 : 1 : 1 : 1. The genotype of the two are
  1. YyRr and yyrr
  2. YYRr and yyrr
  3. YyRR and yyrr
  4. YYRR and yyrr

A
YyRr and yyrr
B
YYRr and yyrr
C
YyRR and yyrr
D
YYRR and yyrr
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Solution
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A cross is made between F1 individual and homozygous recessive individual is called Test cross.

A yellow round seeded plant (YyRr) is corssed with greed wrinkled seeded plant(yyrr). In the next generation, progeny with four types of phenotypes and genotypes are formed in 1:1:1:1 ratio. It is called Test cross.

So, the correct option is ‘YyRr and yyrr’.
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