An artificial satellite moving in circular orbit around the earth has a total ( kinetic + potential ) energy E0. Its potential energy and kinetic energy respectively are
2E0 and −2E0
2E0 and 3E0
2E0 and −E0
−2E0 and −E0
A
2E0 and −2E0
B
2E0 and 3E0
C
2E0 and −E0
D
−2E0 and −E0
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Solution
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From the options itself it is clear that only in option C, when you add PE and KE i.e 2Eo+(−Eo) we get Eo Now Total energy Eo=P.E+K.E=−GMmR+12mv2 When we substitute v=√GMR in K.E, we have K.E=GMm2R
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