In half wave rectifier, a p-n diode with internal resistance 20Ω is used. If the load resistance of 2KΩ is used in the circuit, then the efficiency of this half wave rectifier is (in percentage)
80.4%
40.2%
20%
50%
A
80.4%
B
50%
C
40.2%
D
20%
Open in App
Solution
Verified by Toppr
The efficiency η of half wave rectifier is given by, η=0.406RLrf+RL
Was this answer helpful?
3
Similar Questions
Q1
In half wave rectifier, a p-n diode with internal resistance 20Ω is used. If the load resistance of 2KΩ is used in the circuit, then the efficiency of this half wave rectifier is (in percentage)
View Solution
Q2
A full wave p-n diode rectifier uses a load resistance of 1300Ω. No filter is used. If the internal resistance of each diode is 9Ω, then the efficiency of this full wave rectifier is
View Solution
Q3
A full-wave p-n diode rectifier uses a load resistor of 1500Ω. No filter is used. The forward bias resistance of the diode is 10Ω. the efficiency of the rectifier is
View Solution
Q4
Consider a half wave rectifier with a 500 Ω load operating from 200V(RMS) supply. If the diode have forward resistance Rf equal to 10 Ω, then the regulation is
View Solution
Q5
In a half wave rectifier, the output is taken across a 90Ω load resistor. If the resistance of diode in forward biased condition is 10Ω, the efficiency of rectification of ac power into dc power is