Refractive index of a prism is √7/3 and the angle of prism is 60∘. The minimum angle of incidence of a ray that will be transmitted through the prism is
30∘
45∘
15∘
50∘
A
45∘
B
30∘
C
15∘
D
50∘
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Solution
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A ray is projected on face LM of the prism gets refracted from the two faces of the prism and finally emerges out of it.
For minimum i, the emergent ray must graze on the face LN i-e. e=90o
Using Snell's law for face LN, n2sinr2=n1sine
√73sinr2=1×sin90o
This gives r2=40.89o
As A=r1+r2 ,A=60o
r2=19.11o
Using snell's law for face LN, 1×sini=√73×sin19.11o
This gives i=30o
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