A biconvex lens has a radius of curvature of magnitude 20cm. Which one of the following options best describe the image formed of an object of height 2cm placed 30cm from the lens?
Virtual, upright, height =1cm
Virtual, upright, height =0.5cm
Real, inverted, height =4cm
Real, inverted, height =1cm
A
Real, inverted, height =4cm
B
Real, inverted, height =1cm
C
Virtual, upright, height =1cm
D
Virtual, upright, height =0.5cm
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Solution
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Given,
Radius of curvature, R=20cm
Height of object, h0=2
Object distance, u=30cm
We have, 1f=(μ−1)(1R1−1R2)
=(32−1)[120−(−120)]
⇒1f=(32−1)×220
∴f=20cm
1f=1v−1u
⇒120=1v+130
1v=120−130
=10600
v=60cm
m=hih0=vu
⇒hi=vu×h0
=6030×2=−4cm
so, image is inverted.
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