Charge of 5μC is at each of the vertices of a regular hexagon of side 10cm. Determine the electric potential at the centre of the regular hexagon.
For Hexagonal shape
OA=OB−OC=OD=OE=OF=10cm=0.1m
Potential at O
VO=VA+VB+VC+VD+VE+VF=6VA
Due to equal of charge and distance
VA=VB=VC=VD=VE=VF∴VO=6×14πε0qOA=6×9×109⋅×5×10−60.1=27×105 or VO=2.7×106 volt