For a triangle ABC, which of the following is true?
BC2−AB2=AC2
AB−AC=BC
(AB−AC)>BC
AB−AC<BC
A
AB−AC=BC
B
(AB−AC)>BC
C
AB−AC<BC
D
BC2−AB2=AC2
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Solution
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For any △ABC, the difference between two sides of the triangle should be less than the third side. Thus, AB−AC<BC
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